Class 12 Vector Algebra · Short Answer2 Markscross_product_area
Class 12 Maths · Vector Algebra · Short Answer #60
Find the area of a parallelogram with adjacent sides (1,−1,3) and (2,−7,1).
✅ Step-by-Step Solution
Final Answer: 15√2 square units.
- The area is |a × b|.
- Compute a × b = (20,5,−5), whose squared norm is 400 + 25 + 25 = 450.
- Thus the area is √450 = 15√2 square units.
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] The area is |a × b|.
- [1 mark] Compute a × b = (20,5,−5), whose squared norm is 400 + 25 + 25 = 450.
- [0.5 marks] Thus the area is √450 = 15√2 square units.
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