Mathbee CBSE Mathbee · CBSE Class 12 Maths
NCERT Class 12 · Ch 1 Miscellaneous Exercise · Q1

NCERT Class 12 Maths · Chapter 1 Relations And Functions · Miscellaneous Exercise Question 1

Prove that f:ℝ→(−1,1), f(x)=x/(1+|x|), is one-one and onto.

💡 Concept Hints

  1. Split by the sign of x; on each branch solve the output equation.
  2. Write the defining condition carefully and preserve every domain restriction while simplifying.

✅ Step-by-Step Solution

Final Answer: f is bijective; f⁻¹(y)=y/(1−|y|), −1<y<1.
  1. For every x, |f(x)|=|x|/(1+|x|)<1, so the stated codomain is valid. The sign of a nonzero output equals the input sign.
  2. For y∈[0,1), solve y=x/(1+x) with x≥0 to obtain x=y/(1−y). This is the unique nonnegative solution.
  3. For y∈(−1,0), solve y=x/(1−x) with x<0 to obtain x=y/(1+y). This is the unique negative solution.
  4. The two formulas combine to x=y/(1−|y|). Every y∈(−1,1) has exactly one preimage, proving both onto and one-one.

Master Chapter 1: Relations And Functions

Practise interactive questions, flashcards, visual mind maps, and timed board tests for Relations And Functions.
📘 Chapter Notes & All Exercises 🚀 Open in Interactive Workspace →
Next Question →
Prove that f:ℝ→ℝ, f(x)=x³, is injective.

All Questions in Relations And Functions — Miscellaneous Exercise

Related Questions in Relations And Functions