NCERT Class 12 · Ch 10 Exercise 10.1 · Q1
NCERT Class 12 Maths · Chapter 10 Vector Algebra · Exercise 10.1 Question 1
Represent graphically a displacement of 40 km, 30° east of north.
💡 Concept Hints
- Write the vector components and identify the required direction or geometric relation.
- Use the magnitude, dot-product, cross-product or section formula that matches the requested quantity.
✅ Step-by-Step Solution
Final Answer: Taking east as x and north as y: (20,20√3) km.
- The angle is measured from north toward east, so x=40sin 30°=20 km, y=40cos 30°=20√3 km.
- Draw the vector from the origin to (20,20√3), with length √(20²+(20√3)²)=40 km.
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