NCERT Class 12 · Ch 10 Exercise 10.2 · Q1

NCERT Class 12 Maths · Chapter 10 Vector Algebra · Exercise 10.2 Question 1

Compute magnitudes of a=\(\left[\begin{matrix}1\\1\\1\end{matrix}\right]\), b=\(\left[\begin{matrix}2\\-7\\-3\end{matrix}\right]\), c=\(\left[\begin{matrix}\frac{\sqrt{3}}{3}\\\frac{\sqrt{3}}{3}\\- \frac{\sqrt{3}}{3}\end{matrix}\right]\).

💡 Concept Hints

Write the vector components and identify the required direction or geometric relation.
Use the magnitude, dot-product, cross-product or section formula that matches the requested quantity.

✅ Step-by-Step Solution

Final Answer: √3, √62, 1, respectively.

(1) Sum the squared components: \(3\). The magnitude is its nonnegative square root \(\sqrt{3}\).
(2) Sum the squared components: \(62\). The magnitude is its nonnegative square root \(\sqrt{62}\).
(3) Sum the squared components: \(1\). The magnitude is its nonnegative square root \(1\).

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NCERT Class 12 Maths · Chapter 10 Vector Algebra · Exercise 10.2 Question 1

💡 Concept Hints

✅ Step-by-Step Solution

Master Chapter 10: Vector Algebra

All Questions in Vector Algebra — Exercise 10.2

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