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NCERT Class 12 · Ch 9 Exercise 9.5 · Q2

NCERT Class 12 Maths · Chapter 9 Differential Equations · Exercise 9.5 Question 2

Solve y′+\(3\) y=\(e^{- 2 x}\).

💡 Concept Hints

  1. Identify the domain and the inner and outer functions, or the relevant one-sided limits.
  2. Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.

✅ Step-by-Step Solution

Final Answer: y = \(\left(C + e^{x}\right) e^{- 3 x}\), on intervals where the original equation is defined.
  1. Write y′ + \(3\) y = \(e^{- 2 x}\); work on intervals where the original equation is defined.
  2. An integrating factor is μ=\(e^{3 x}\), since μ′/μ=\(3\).
  3. Multiply through: d(μy)/dx = \(e^{x}\).
  4. Integrate the right side: \(e^{x}\). Thus μy=\(e^{x}\)+C.
  5. Therefore y = \(\left(C + e^{x}\right) e^{- 3 x}\).

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