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NCERT Class 12 · Ch 9 Exercise 9.5 · Q3

NCERT Class 12 Maths · Chapter 9 Differential Equations · Exercise 9.5 Question 3

Solve y′+\(\frac{1}{x}\) y=\(x^{2}\).

💡 Concept Hints

  1. Identify the domain and the inner and outer functions, or the relevant one-sided limits.
  2. Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.

✅ Step-by-Step Solution

Final Answer: y = \(\frac{4 C + x^{4}}{4 x}\), on x>0 or x<0.
  1. Write y′ + \(\frac{1}{x}\) y = \(x^{2}\); work on x>0 or x<0.
  2. An integrating factor is μ=\(x\), since μ′/μ=\(\frac{1}{x}\).
  3. Multiply through: d(μy)/dx = \(x^{3}\).
  4. Integrate the right side: \(\frac{x^{4}}{4}\). Thus μy=\(\frac{x^{4}}{4}\)+C.
  5. Therefore y = \(\frac{4 C + x^{4}}{4 x}\).

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