NCERT Class 12 · Ch 2 Exercise 2.1 · Q14
NCERT Class 12 Maths · Chapter 2 Inverse Trigonometric Functions · Exercise 2.1 Question 14
Evaluate tan⁻¹(√3)−sec⁻¹(−2).
💡 Concept Hints
- Recall the principal range of the inverse function before simplifying.
- Find an angle with the required trigonometric value, then verify it belongs to the principal range.
✅ Step-by-Step Solution
Final Answer: B: −π/3.
- tan⁻¹(√3)=π/3.
- sec⁻¹(−2)=cos⁻¹(−1/2)=2π/3 in the secant-inverse principal range.
- Subtract to get −π/3, option B.
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