NCERT Class 12 · Ch 2 Exercise 2.1 · Q7
NCERT Class 12 Maths · Chapter 2 Inverse Trigonometric Functions · Exercise 2.1 Question 7
Find the principal value of sec⁻¹(2/√3).
💡 Concept Hints
- Recall the principal range of the inverse function before simplifying.
- Find an angle with the required trigonometric value, then verify it belongs to the principal range.
✅ Step-by-Step Solution
Final Answer: π/6
- The principal range is [0,π]∖{π/2}.
- sec(π/6)=2/√3.
- The angle π/6 belongs to that range, so it is the required value.
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