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NCERT Class 12 · Ch 3 Exercise 3.2 · Q1

NCERT Class 12 Maths · Chapter 3 Matrices · Exercise 3.2 Question 1

Let A = \(\left[\begin{matrix}2 & 4\\3 & 2\end{matrix}\right]\), B = \(\left[\begin{matrix}1 & 3\\-2 & 5\end{matrix}\right]\), C = \(\left[\begin{matrix}-2 & 5\\3 & 4\end{matrix}\right]\). Find (i) A+B, (ii) A−B, (iii) 3A−C, (iv) AB, (v) BA.

💡 Concept Hints

  1. Check the matrix orders and the meaning of the requested operation before calculating.
  2. Keep row and column indices in order. Compare corresponding entries only after the matrix expressions have compatible dimensions.

✅ Step-by-Step Solution

Final Answer: \(\left[\begin{matrix}3 & 7\\1 & 7\end{matrix}\right]\); \(\left[\begin{matrix}1 & 1\\5 & -3\end{matrix}\right]\); \(\left[\begin{matrix}8 & 7\\6 & 2\end{matrix}\right]\); \(\left[\begin{matrix}-6 & 26\\-1 & 19\end{matrix}\right]\); \(\left[\begin{matrix}11 & 10\\11 & 2\end{matrix}\right]\)
  1. Addition and subtraction are entrywise; scalar multiplication multiplies every entry.
  2. A+B = \(\left[\begin{matrix}3 & 7\\1 & 7\end{matrix}\right]\).
  3. A−B = \(\left[\begin{matrix}1 & 1\\5 & -3\end{matrix}\right]\).
  4. 3A−C = \(\left[\begin{matrix}8 & 7\\6 & 2\end{matrix}\right]\).
  5. For AB, the inner dimensions agree: 2. Its order is 2×2. Use cᵢⱼ=Σₖaᵢₖbₖⱼ.
  6. Row 1: \(c_{11}=(2)(1) + (4)(-2)=-6,\quad c_{12}=(2)(3) + (4)(5)=26\).
  7. Row 2: \(c_{21}=(3)(1) + (2)(-2)=-1,\quad c_{22}=(3)(3) + (2)(5)=19\).
  8. AB = \(\left[\begin{matrix}-6 & 26\\-1 & 19\end{matrix}\right]\).
  9. For BA, the inner dimensions agree: 2. Its order is 2×2. Use cᵢⱼ=Σₖaᵢₖbₖⱼ.
  10. Row 1: \(c_{11}=(1)(2) + (3)(3)=11,\quad c_{12}=(1)(4) + (3)(2)=10\).
  11. Row 2: \(c_{21}=(-2)(2) + (5)(3)=11,\quad c_{22}=(-2)(4) + (5)(2)=2\).
  12. BA = \(\left[\begin{matrix}11 & 10\\11 & 2\end{matrix}\right]\).

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