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NCERT Class 12 · Ch 3 Exercise 3.3 · Q1

NCERT Class 12 Maths · Chapter 3 Matrices · Exercise 3.3 Question 1

Find the transposes of (1) \(\left[\begin{matrix}5\\1\\2\\-1\end{matrix}\right]\); (2) \(\left[\begin{matrix}1 & -1\\2 & 3\end{matrix}\right]\); (3) \(\left[\begin{matrix}-1 & 5 & 6\\3 & 5 & 6\\2 & 3 & -1\end{matrix}\right]\).

💡 Concept Hints

  1. Check the matrix orders and the meaning of the requested operation before calculating.
  2. Keep row and column indices in order. Compare corresponding entries only after the matrix expressions have compatible dimensions.

✅ Step-by-Step Solution

Final Answer: \(\left[\begin{matrix}5 & 1 & 2 & -1\end{matrix}\right]\); \(\left[\begin{matrix}1 & 2\\-1 & 3\end{matrix}\right]\); \(\left[\begin{matrix}-1 & 3 & 2\\5 & 5 & 3\\6 & 6 & -1\end{matrix}\right]\)
  1. A transpose turns row i into column i: (Aᵀ)ᵢⱼ=Aⱼᵢ.
  2. Part (1): the original order is 4×1; the transpose has order 1×4 and equals \(\left[\begin{matrix}5 & 1 & 2 & -1\end{matrix}\right]\).
  3. Part (2): the original order is 2×2; the transpose has order 2×2 and equals \(\left[\begin{matrix}1 & 2\\-1 & 3\end{matrix}\right]\).
  4. Part (3): the original order is 3×3; the transpose has order 3×3 and equals \(\left[\begin{matrix}-1 & 3 & 2\\5 & 5 & 3\\6 & 6 & -1\end{matrix}\right]\).

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