NCERT Class 12 Maths · Chapter 3 Matrices · Exercise 3.3 Question 7

✅ Step-by-Step Solution

1. (i) Transposing gives \(\left[\begin{matrix}1 & -1 & 5\\-1 & 2 & 1\\5 & 1 & 3\end{matrix}\right]\), identical to A, so A is symmetric.
2. (ii) Transposing gives \(\left[\begin{matrix}0 & -1 & 1\\1 & 0 & -1\\-1 & 1 & 0\end{matrix}\right]\), equal to −B, so B is skew symmetric. Its diagonal entries are all zero.