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NCERT Class 12 · Ch 3 Miscellaneous Exercise · Q8

NCERT Class 12 Maths · Chapter 3 Matrices · Miscellaneous Exercise Question 8

Find X such that X\(\left[\begin{matrix}1 & 2 & 3\\4 & 5 & 6\end{matrix}\right]\) = \(\left[\begin{matrix}-7 & -8 & -9\\2 & 4 & 6\end{matrix}\right]\).

💡 Concept Hints

  1. Check the matrix orders and the meaning of the requested operation before calculating.
  2. Keep row and column indices in order. Compare corresponding entries only after the matrix expressions have compatible dimensions.

✅ Step-by-Step Solution

Final Answer: \(\left[\begin{matrix}1 & -2\\2 & 0\end{matrix}\right]\)
  1. The right side has 2 rows while the factor A is 2×3, so X must be 2×2. Put X=[[a,b],[c,d]].
  2. Equating product entries gives a+4b=−7,2a+5b=−8,3a+6b=−9; c+4d=2,2c+5d=4,3c+6d=6.
  3. The first two equations in each row give a=1,b=−2,c=2,d=0; each remaining equation is satisfied.
  4. Thus X=\(\left[\begin{matrix}1 & -2\\2 & 0\end{matrix}\right]\), and direct multiplication verifies the result.

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