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NCERT Class 12 · Ch 13 Exercise 13.3 · Q10

NCERT Class 12 Maths · Chapter 13 Probability · Exercise 13.3 Question 10

A girl rolls a fair die. On 5 or 6 she tosses a coin three times, otherwise once. Given exactly one head, find P(die was 1,2,3 or 4).
Exercise 13.3 Q10: priors, likelihoods and joints
Exercise 13.3 Q10: priors, likelihoods and joints

💡 Concept Hints

  1. Define the events and identify which event is being conditioned on.
  2. Use P(E|F)=P(E∩F)/P(F), or separate the possible sources before applying total probability and Bayes.

✅ Step-by-Step Solution

Final Answer: die 1–4: 8/11
  1. Use the mutually exclusive source events with prior probabilities die 1–4=2/3, die 5–6=1/3.
  2. One toss gives exactly one head with probability 1/2. Three fair tosses give exactly one head in three of eight strings, hence probability 3/8.
  3. The observation likelihoods in the same order are 1/2, 3/8. Multiply each prior by its likelihood to get joint probabilities 1/3, 1/8.
  4. Total probability of the observation is 1/3 + 1/8 = 11/24.
  5. Bayes: P(die 1–4 | observation) = 1/3 / 11/24 = 8/11.

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