Class 12 Three Dimensional Geometry · Conceptual Answer1 Marksequations_of_lines
Class 12 Maths · Three Dimensional Geometry · Conceptual Answer #69
Find vector and Cartesian equations through (3,4,5) with direction (2,2,-3).
✅ Step-by-Step Solution
Final Answer: r=(3,4,5)+t(2,2,-3), t∈ℝ; (x−(3))/(2)=(y−(4))/(2)=(z−(5))/(-3).
- Use r=A+td, equate coordinates and eliminate t; any coordinate with zero direction remains fixed.
- r=(3,4,5)+t(2,2,-3), t∈ℝ; (x−(3))/(2)=(y−(4))/(2)=(z−(5))/(-3).
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] Use r=A+td, equate coordinates and eliminate t; any coordinate with zero direction remains fixed.
- [0.5 marks] r=(3,4,5)+t(2,2,-3), t∈ℝ; (x−(3))/(2)=(y−(4))/(2)=(z−(5))/(-3).
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