Class 12 Three Dimensional Geometry · Conceptual Answer1 Marksequations_of_lines
Class 12 Maths · Three Dimensional Geometry · Conceptual Answer #70
Find vector and Cartesian equations through (2,-1,4) with direction (1,1,-2).
✅ Step-by-Step Solution
Final Answer: r=(2,-1,4)+t(1,1,-2), t∈ℝ; (x−(2))/(1)=(y−(-1))/(1)=(z−(4))/(-2).
- Use r=A+td, equate coordinates and eliminate t; any coordinate with zero direction remains fixed.
- r=(2,-1,4)+t(1,1,-2), t∈ℝ; (x−(2))/(1)=(y−(-1))/(1)=(z−(4))/(-2).
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] Use r=A+td, equate coordinates and eliminate t; any coordinate with zero direction remains fixed.
- [0.5 marks] r=(2,-1,4)+t(1,1,-2), t∈ℝ; (x−(2))/(1)=(y−(-1))/(1)=(z−(4))/(-2).
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