Class 12 Three Dimensional Geometry · Conceptual Answer1 Marksequations_of_lines
Class 12 Maths · Three Dimensional Geometry · Conceptual Answer #73
Find vector and Cartesian equations through (-2,1,3) with direction (5,0,-5).
✅ Step-by-Step Solution
Final Answer: r=(-2,1,3)+t(5,0,-5), t∈ℝ; (x−(-2))/(5)=(z−(3))/(-5); y=1.
- Use r=A+td, equate coordinates and eliminate t; any coordinate with zero direction remains fixed.
- r=(-2,1,3)+t(5,0,-5), t∈ℝ; (x−(-2))/(5)=(z−(3))/(-5); y=1.
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] Use r=A+td, equate coordinates and eliminate t; any coordinate with zero direction remains fixed.
- [0.5 marks] r=(-2,1,3)+t(5,0,-5), t∈ℝ; (x−(-2))/(5)=(z−(3))/(-5); y=1.
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