Class 12 Three Dimensional Geometry · Conceptual Answer1 Marksequations_of_lines
Class 12 Maths · Three Dimensional Geometry · Conceptual Answer #72
Find vector and Cartesian equations through (3,-4,3) with direction (-5,7,2).
✅ Step-by-Step Solution
Final Answer: r=(3,-4,3)+t(-5,7,2), t∈ℝ; (x−(3))/(-5)=(y−(-4))/(7)=(z−(3))/(2).
- Use r=A+td, equate coordinates and eliminate t; any coordinate with zero direction remains fixed.
- r=(3,-4,3)+t(-5,7,2), t∈ℝ; (x−(3))/(-5)=(y−(-4))/(7)=(z−(3))/(2).
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] Use r=A+td, equate coordinates and eliminate t; any coordinate with zero direction remains fixed.
- [0.5 marks] r=(3,-4,3)+t(-5,7,2), t∈ℝ; (x−(3))/(-5)=(y−(-4))/(7)=(z−(3))/(2).
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