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Class 12 Applications Of Integrals · Short Answer2 Marksarea_by_integration

Class 12 Maths · Applications Of Integrals · Short Answer #37

Find the area bounded by y=x²,x=2,x=3 and the x-axis.
Computed region for practice_vsa 2
Computed region for practice_vsa 2

✅ Step-by-Step Solution

Final Answer: \(\frac{19}{3}\) square units
  1. The parabola is positive throughout [2,3], so the strip height is x². The strip widths are \(x^{2}\) for x∈\(\left[2, 3\right]\).
  2. Primitive \(\frac{x^{3}}{3}\), endpoint difference \(\frac{19}{3}\).
  3. Therefore the area is \(\frac{19}{3}\) square units.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] The parabola is positive throughout [2,3], so the strip height is x². The strip widths are \(x^{2}\) for x∈\(\left[2, 3\right]\).
  • [1 mark] Primitive \(\frac{x^{3}}{3}\), endpoint difference \(\frac{19}{3}\).
  • [0.5 marks] Therefore the area is \(\frac{19}{3}\) square units.

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