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Class 12 Applications Of Integrals · Short Answer2 Marksarea_by_integration

Class 12 Maths · Applications Of Integrals · Short Answer #10

Sketch the region between y=√(4−x²) and the x-axis, and find its area by integration.
Computed region for vsa 2
Computed region for vsa 2

✅ Step-by-Step Solution

Final Answer: \(2 \pi\) square units
  1. The curve is the upper semicircle x²+y²=4, with x-axis endpoints (−2,0),(2,0). The strip widths are \(\sqrt{4 - x^{2}}\) for x∈\(\left[-2, 2\right]\).
  2. Primitive \(\frac{x \sqrt{4 - x^{2}}}{2} + 2 \operatorname{asin}{\left(\frac{x}{2} \right)}\), endpoint difference \(2 \pi\).
  3. Therefore the area is \(2 \pi\) square units.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] The curve is the upper semicircle x²+y²=4, with x-axis endpoints (−2,0),(2,0). The strip widths are \(\sqrt{4 - x^{2}}\) for x∈\(\left[-2, 2\right]\).
  • [1 mark] Primitive \(\frac{x \sqrt{4 - x^{2}}}{2} + 2 \operatorname{asin}{\left(\frac{x}{2} \right)}\), endpoint difference \(2 \pi\).
  • [0.5 marks] Therefore the area is \(2 \pi\) square units.

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