Class 12 Determinants · Conceptual Answer1 Marksmatrix_inverse
Class 12 Maths · Determinants · Conceptual Answer #87
Find A⁻¹ for A=\(\begin{bmatrix}3 & -4\\1 & -1\end{bmatrix}\).
✅ Step-by-Step Solution
Final Answer: \(\begin{bmatrix}-1 & 4\\-1 & 3\end{bmatrix}\)
- det(A)=−3+4=1, so A⁻¹=adj(A)=[[−1,4],[−1,3]].
- \(\begin{bmatrix}-1 & 4\\-1 & 3\end{bmatrix}\)
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] det(A)=−3+4=1, so A⁻¹=adj(A)=[[−1,4],[−1,3]].
- [0.5 marks] \(\begin{bmatrix}-1 & 4\\-1 & 3\end{bmatrix}\)
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