Class 12 Probability · Short Answer2 Marksconditional_probability
Class 12 Maths · Probability · Short Answer #47
Given P(A)=0.6, P(B)=0.5 and P(B|A)=0.4, find P(A∪B) and P(A|B).
✅ Step-by-Step Solution
Final Answer: P(A∪B)=0.86; P(A|B)=0.48
- First P(A∩B)=P(A)P(B|A)=0.6·0.4=0.24.
- P(A∪B)=0.6+0.5−0.24=0.86. Also P(A|B)=0.24/0.5=0.48.
- Therefore the requested values are 0.86 and 0.48, respectively.
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] First P(A∩B)=P(A)P(B|A)=0.6·0.4=0.24.
- [1 mark] P(A∪B)=0.6+0.5−0.24=0.86. Also P(A|B)=0.24/0.5=0.48.
- [0.5 marks] Therefore the requested values are 0.86 and 0.48, respectively.
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