Mathbee CBSE Mathbee · CBSE Class 12 Maths
Class 12 Probability · Short Answer2 Marksindependence

Class 12 Maths · Probability · Short Answer #48

Students A,B arrive on time independently with probabilities 2/7 and 4/7. Find P(exactly one is on time).

✅ Step-by-Step Solution

Final Answer: 26/49
  1. The disjoint cases are A on time and B late, or A late and B on time.
  2. P=(2/7)(3/7)+(5/7)(4/7)=6/49+20/49.
  3. Thus P=26/49.

📋 CBSE Stepwise Marking Scheme

  • [0.5 marks] The disjoint cases are A on time and B late, or A late and B on time.
  • [1 mark] P=(2/7)(3/7)+(5/7)(4/7)=6/49+20/49.
  • [0.5 marks] Thus P=26/49.

Master Chapter 13: Probability

Practise interactive questions, flashcards, visual mind maps, and timed board tests for Probability.
📘 Chapter Notes & All Exercises 🚀 Open Interactive Workspace →
← Previous Question
Given P(A)=0.6, P(B)=0.5 and P(B|A)=0.4, find P(A∪B) and P(A|B).
Next Question →
Draw two chocolates uniformly without replacement from 2 milk and 4…

More Practice Questions in Probability

Related Questions in Probability