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CBSE Class 12 Mathematics 2026 Main Paper 65(B) · Q374 Marksparametric_derivatives

CBSE Class 12 Mathematics 2026 Main Paper 65(B) · Question 37 (Continuity And Differentiability)

A class is studying dy/dx=(dy/dt)/(dx/dt) for parametrically defined curves on regular branches.
Part (1) 1 Marks
For x=at³, y=at⁵, find dy/dx.
Answer: 5t²/3 for a≠0,t≠0.
  1. Differentiate to get dx/dt=3at² and dy/dt=5at⁴.
  2. Take the quotient on regular branches.
Part (2) 1 Marks
For x=t+1/t, y=t−1/t, find dy/dx.
Answer: (t²+1)/(t²−1), t≠0,±1.
  1. The derivatives are 1−1/t² and 1+1/t².
  2. Take their quotient where the first is nonzero.
Part (3) 2 Marks
For x=2sin t+sin2t and y=2cos t+cos2t, find dy/dx at t=π/6.
Answer: −1.
  1. The t-derivatives are 2cos t+2cos2t and −2sin t−2sin2t.
  2. At π/6 these are √3+1 and −1−√3.
  3. Their quotient is −1.
Part (4) 2 Marks
For x=a(cos t+ln tan(t/2)) and y=a sin t, find dy/dx on regular real branches.
Answer: tan t.
  1. The derivative of ln tan(t/2) is csc t on its real domain.
  2. Thus dx/dt=a(−sin t+csc t)=a cos²t/sin t and dy/dt=a cos t.
  3. Their quotient is tan t where a≠0, sin t≠0 and cos t≠0.

✅ Step-by-Step Solution

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