NCERT Class 12 · Ch 5 Exercise 5.1 · Q1
NCERT Class 12 Maths · Chapter 5 Continuity And Differentiability · Exercise 5.1 Question 1
Prove f(x)=5x−3 is continuous at x=0,−3,5.
💡 Concept Hints
- Identify the domain and the inner and outer functions, or the relevant one-sided limits.
- Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.
✅ Step-by-Step Solution
Final Answer: Continuous at all three points.
- A polynomial is continuous at every real point. More explicitly limₓ→ₐ(5x−3)=5a−3=f(a).
- At a=0,−3,5 the limit and function value are respectively −3,−18,22.
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