NCERT Class 12 · Ch 5 Exercise 5.1 · Q20
NCERT Class 12 Maths · Chapter 5 Continuity And Differentiability · Exercise 5.1 Question 20
Is f(x)=x²−sin x+5 continuous at π?
💡 Concept Hints
- Identify the domain and the inner and outer functions, or the relevant one-sided limits.
- Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.
✅ Step-by-Step Solution
Final Answer: Yes; limit and value are π²+5.
- The polynomial x²+5 and sine are continuous on R. Their difference is continuous.
- Substitution at π yields π²−sin π+5=π²+5.
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