NCERT Class 12 · Ch 5 Exercise 5.1 · Q30
NCERT Class 12 Maths · Chapter 5 Continuity And Differentiability · Exercise 5.1 Question 30
Find a,b so f(x)=5 for x≤2, ax+b for 2<x<10, and 21 for x≥10 is continuous.
💡 Concept Hints
- Identify the domain and the inner and outer functions, or the relevant one-sided limits.
- Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.
✅ Step-by-Step Solution
Final Answer: a=2, b=1.
- Matching at 2 gives 2a+b=5; matching at 10 gives 10a+b=21.
- Subtract: 8a=16, so a=2 and b=1. All branches are continuous and both junctions now match.
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