Mathbee CBSE Mathbee · CBSE Class 12 Maths
NCERT Class 12 · Ch 5 Miscellaneous Exercise · Q13

NCERT Class 12 Maths · Chapter 5 Continuity And Differentiability · Miscellaneous Exercise Question 13

Differentiate y=sin⁻¹x+sin⁻¹√(1−x²), 0<x<1.

💡 Concept Hints

  1. Identify the domain and the inner and outer functions, or the relevant one-sided limits.
  2. Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.

✅ Step-by-Step Solution

Final Answer: 0.
  1. Set u=sin⁻¹x∈(0,π/2). Then √(1−x²)=cos u and sin⁻¹(cos u)=π/2−u.
  2. Thus y=π/2 is constant and dy/dx=0.

Master Chapter 5: Continuity And Differentiability

Practise interactive questions, flashcards, visual mind maps, and timed board tests for Continuity And Differentiability.
📘 Chapter Notes & All Exercises 🚀 Open Interactive Workspace →
← Previous Question
Find dy/dx for y=12(1−cos t), x=10(t−sin t), −π/2<t<π/2.
Next Question →
If x√(1+y)+y√(1+x)=0, −1<x<1, prove y′=−1/(1+x)².

All Questions in Continuity And Differentiability — Miscellaneous Exercise

Related Questions in Continuity And Differentiability