NCERT Class 12 · Ch 2 Exercise 2.2 · Q12
NCERT Class 12 Maths · Chapter 2 Inverse Trigonometric Functions · Exercise 2.2 Question 12
Evaluate tan(sin⁻¹(3/5)+cot⁻¹(3/2)).
💡 Concept Hints
- Recall the principal range of the inverse function before simplifying.
- Find an angle with the required trigonometric value, then verify it belongs to the principal range.
✅ Step-by-Step Solution
Final Answer: 17/6
- Put α=sin⁻¹(3/5), β=cot⁻¹(3/2); both are acute.
- cos α=4/5, so tan α=3/4. Since cot β=3/2, tan β=2/3.
- The addition formula gives (3/4+2/3)/(1−(3/4)(2/3))=(17/12)/(1/2)=17/6.
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