NCERT Class 12 · Ch 2 Exercise 2.2 · Q15
NCERT Class 12 Maths · Chapter 2 Inverse Trigonometric Functions · Exercise 2.2 Question 15
Evaluate tan⁻¹(√3)−cot⁻¹(−√3).
💡 Concept Hints
- Recall the principal range of the inverse function before simplifying.
- Find an angle with the required trigonometric value, then verify it belongs to the principal range.
✅ Step-by-Step Solution
Final Answer: B: −π/2.
- tan⁻¹(√3)=π/3.
- In the NCERT cotangent-inverse range (0,π), cot⁻¹(−√3)=5π/6.
- The difference is π/3−5π/6=−π/2, option B.
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