Class 12 Three Dimensional Geometry · Conceptual Answer1 Marksequations_of_lines
Class 12 Maths · Three Dimensional Geometry · Conceptual Answer #71
Find vector and Cartesian equations through (-2,4,-5) with direction (3,-5,6).
✅ Step-by-Step Solution
Final Answer: r=(-2,4,-5)+t(3,-5,6), t∈ℝ; (x−(-2))/(3)=(y−(4))/(-5)=(z−(-5))/(6).
- Use r=A+td, equate coordinates and eliminate t; any coordinate with zero direction remains fixed.
- r=(-2,4,-5)+t(3,-5,6), t∈ℝ; (x−(-2))/(3)=(y−(4))/(-5)=(z−(-5))/(6).
📋 CBSE Stepwise Marking Scheme
- [0.5 marks] Use r=A+td, equate coordinates and eliminate t; any coordinate with zero direction remains fixed.
- [0.5 marks] r=(-2,4,-5)+t(3,-5,6), t∈ℝ; (x−(-2))/(3)=(y−(4))/(-5)=(z−(-5))/(6).
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