Mathbee CBSE Mathbee · CBSE Class 12 Maths
NCERT Class 12 · Ch 11 Exercise 11.2 · Q13

NCERT Class 12 Maths · Chapter 11 Three Dimensional Geometry · Exercise 11.2 Question 13

Find the shortest distance between (x+1)/7=(y+1)/(−6)=(z+1) and (x−3)=(y−5)/(−2)=(z−7).
Two line segments and their shortest connector
Two line segments and their shortest connector

💡 Concept Hints

  1. Identify the base point and a nonzero direction before applying a vector formula.
  2. Use dot products for angles, proportional directions for parallelism, and a triple product for skew-line distance.

✅ Step-by-Step Solution

Final Answer: 2*sqrt(29)
  1. For nonparallel directions, D=|(B−A)·(d×e)|/|d×e|.
  2. Here B−A=(4,6,8), d×e=(-4,-6,-8).
  3. The numerator is 116 and the denominator is 2*sqrt(29).
  4. Therefore D=2*sqrt(29).

Master Chapter 11: Three Dimensional Geometry

Practise interactive questions, flashcards, visual mind maps, and timed board tests for Three Dimensional Geometry.
📘 Chapter Notes & All Exercises 🚀 Open in Interactive Workspace →
← Previous Question
Find the shortest distance between r=(1,2,1)+t(1,−1,1) and…
Next Question →
Find the shortest distance between r=(1,2,3)+t(1,−3,2) and…

All Questions in Three Dimensional Geometry — Exercise 11.2

Related Questions in Three Dimensional Geometry