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NCERT Class 12 · Ch 11 Exercise 11.2 · Q6

NCERT Class 12 Maths · Chapter 11 Three Dimensional Geometry · Exercise 11.2 Question 6

Find the Cartesian equation through (−2,4,−5) parallel to (x+3)/3=(y−4)/5=(z+8)/6.

💡 Concept Hints

  1. Identify the base point and a nonzero direction before applying a vector formula.
  2. Use dot products for angles, proportional directions for parallelism, and a triple product for skew-line distance.

✅ Step-by-Step Solution

Final Answer: r=(-2,4,-5)+t(3,5,6), t∈ℝ; Cartesian: (x−(-2))/(3)=(y−(4))/(5)=(z−(-5))/(6).
  1. A line through base A in nonzero direction d has r=A+td.
  2. Here A=(-2,4,-5), d=(3,5,6).
  3. Equating components gives r=(-2,4,-5)+t(3,5,6), t∈ℝ. Eliminating t gives (x−(-2))/(3)=(y−(4))/(5)=(z−(-5))/(6).

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