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NCERT Class 12 · Ch 6 Exercise 6.3 · Q17

NCERT Class 12 Maths · Chapter 6 Applications Of Derivatives · Exercise 6.3 Question 17

Cut equal corner squares from a 18 cm × 18 cm tin sheet and fold an open box. Find the cut size maximizing volume.
Optimal box net: cut 3 cm squares
Optimal box net: cut 3 cm squares

💡 Concept Hints

  1. Identify the domain and the inner and outer functions, or the relevant one-sided limits.
  2. Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.

✅ Step-by-Step Solution

Final Answer: Cut side 3 cm; maximum volume 432 cm³.
  1. If cut side is x, the box has base (18−2x)×(18−2x), height x, and 0<x<9.0.
  2. V(x)=\(x \left(18 - 2 x\right)^{2}\); V′=\(12 \left(x - 9\right) \left(x - 3\right)\).
  3. The only stationary point in the feasible interval is x=3. The derivative changes from positive to negative there, while volume tends to zero at the feasible endpoints.
  4. Therefore the maximum volume is V(3)=432 cm³.

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