NCERT Class 12 · Ch 6 Exercise 6.3 · Q8
NCERT Class 12 Maths · Chapter 6 Applications Of Derivatives · Exercise 6.3 Question 8
Where on [0,2π] does sin 2x attain its maximum?
💡 Concept Hints
- Identify the domain and the inner and outer functions, or the relevant one-sided limits.
- Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.
✅ Step-by-Step Solution
Final Answer: x=π/4 and 5π/4; maximum 1.
- sin 2x≤1, with equality if 2x=π/2+2nπ.
- Thus x=π/4+nπ. The two such values in [0,2π] are π/4 and 5π/4.
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