Mathbee CBSE Mathbee · CBSE Class 12 Maths
NCERT Class 12 · Ch 9 Exercise 9.3 · Q3

NCERT Class 12 Maths · Chapter 9 Differential Equations · Exercise 9.3 Question 3

Solve y′+y=1, y≠1.

💡 Concept Hints

  1. Identify the domain and the inner and outer functions, or the relevant one-sided limits.
  2. Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.

✅ Step-by-Step Solution

Final Answer: y=1+Ce^(−x), C≠0.
  1. Separate dy/(1−y)=dx. Integration gives −log|1−y|=x+C.
  2. Thus y=1+Ce^(−x), C≠0 under y≠1.
  3. Differentiate the resulting relation to recover the equation on intervals where the original expressions and the required slope are defined.

Master Chapter 9: Differential Equations

Practise interactive questions, flashcards, visual mind maps, and timed board tests for Differential Equations.
📘 Chapter Notes & All Exercises 🚀 Open Interactive Workspace →
← Previous Question
Solve y′=√(4−y²), −2<y<2.
Next Question →
Solve sec²x tan y dx+sec²y tan x dy=0.

All Questions in Differential Equations — Exercise 9.3

Related Questions in Differential Equations