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NCERT Class 12 · Ch 9 Exercise 9.3 · Q4

NCERT Class 12 Maths · Chapter 9 Differential Equations · Exercise 9.3 Question 4

Solve sec²x tan y dx+sec²y tan x dy=0.

💡 Concept Hints

  1. Identify the domain and the inner and outer functions, or the relevant one-sided limits.
  2. Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.

✅ Step-by-Step Solution

Final Answer: \(\tan{\left(x \right)} \tan{\left(y \right)}\) = C.
  1. The left side is exactly d(tan x tan y).
  2. Hence tan x tan y=C on the original secant domain. This implicit form also retains zero-constant branches.
  3. Differentiate the resulting relation to recover the equation on intervals where the original expressions and the required slope are defined.

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