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NCERT Class 12 · Ch 7 Exercise 7.9 · Q5

NCERT Class 12 Maths · Chapter 7 Integrals · Exercise 7.9 Question 5

Evaluate \(\int\limits_{0}^{\frac{\pi}{2}} \frac{\sin{\left(x \right)}}{\cos^{2}{\left(x \right)} + 1}\, dx\).

💡 Concept Hints

  1. Identify the domain and the inner and outer functions, or the relevant one-sided limits.
  2. Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.

✅ Step-by-Step Solution

Final Answer: \(\frac{\pi}{4}\)
  1. Work on each open interval where the original integrand is real and defined.
  2. u=cos x, du=−sin x dx.
  3. An antiderivative is F(x)=\(- \operatorname{atan}{\left(\cos{\left(x \right)} \right)}\).
  4. At the upper and lower limits, F(b)=\(0\) and F(a)=\(- \frac{\pi}{4}\).
  5. By the fundamental theorem (using one-sided limits for any integrable endpoint), I=F(b)−F(a)=\(\frac{\pi}{4}\).

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