NCERT Class 12 Maths · Chapter 13 Probability · Exercise 13.1 Question 15
Throw a die; on a multiple of 3 throw it again, otherwise toss a coin. Find P(coin tail | at least one die shows 3).
💡 Concept Hints
Define the events and identify which event is being conditioned on.
Use P(E|F)=P(E∩F)/P(F), or separate the possible sources before applying total probability and Bayes.
✅ Step-by-Step Solution
Final Answer: 0.
A coin is tossed only if the first die is 1,2,4 or 5. On every such path no die showed 3.
If at least one die shows 3, the path is in the two-die branch, so the coin-tail event cannot occur. The conditioning event has positive probability 1/6+1/36=7/36; its intersection with tail has probability zero.
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