NCERT Class 12 · Ch 13 Exercise 13.1 · Q9
NCERT Class 12 Maths · Chapter 13 Probability · Exercise 13.1 Question 9
Mother, father and son line up at random. Find P(son at an end | father in middle).
💡 Concept Hints
- Define the events and identify which event is being conditioned on.
- Use P(E|F)=P(E∩F)/P(F), or separate the possible sources before applying total probability and Bayes.
✅ Step-by-Step Solution
Final Answer: 1.
- With father fixed in the middle, the two possible orders are MFS and SFM.
- The son is at an end in both, so the conditional probability is 2/2=1.
- family: the conditioned space has 2 equally likely outcomes, of which 2 satisfy the event. Thus P=1.
Master Chapter 13: Probability
Practise interactive questions, flashcards, visual mind maps, and timed board tests for Probability.
← Previous Question
A fair die is thrown three times. Find P(third is 4 | first is 6 and…
Next Question →Black and red dice are rolled. Find (a) P(sum>9 | black=5), (b)…
Related Questions in Probability
Class 12 Probability · Mcq Single Correct
Given P(A)=4/5 and P(A∩B)=7/10, find P(B|A).
Class 12 Probability · Mcq Single Correct
Five independent fair coins are tossed. Find the probability of at least one head.
Class 12 Probability · Mcq Single Correct
Given P(A|B)=0.3, P(A)=0.4, P(B)=0.8, find P(B|A).
Class 12 Probability · Mcq Single Correct
Two independent fair dice have sum 9. Find the conditional probability that at least one die…
Class 12 Probability · Mcq Single Correct
Choose an ordered pair (a,b) uniformly with distinct a,b from {1,2,3,4,5}. Find P(a/b is an…
Class 12 Probability · Mcq Single Correct
Given P(A)=0.4, P(B)=0.3 and P(A∪B)=0.5, find P(B′∩A).