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NCERT Class 12 · Ch 13 Exercise 13.1 · Q6

NCERT Class 12 Maths · Chapter 13 Probability · Exercise 13.1 Question 6

A fair coin is tossed three times. Find P(E|F): (i) E=head on third toss, F=heads on first two; (ii) E=at least two heads, F=at most two heads; (iii) E=at most two tails, F=at least one tail.

💡 Concept Hints

  1. Define the events and identify which event is being conditioned on.
  2. Use P(E|F)=P(E∩F)/P(F), or separate the possible sources before applying total probability and Bayes.

✅ Step-by-Step Solution

Final Answer: (i) 1/2; (ii) 3/7; (iii) 6/7.
  1. Assume independent fair tosses; the eight ordered H/T strings are equally likely.
  2. Condition by restricting the sample space to F before counting E∩F.
  3. i: the conditioned space has 2 equally likely outcomes, of which 1 satisfy the event. Thus P=1/2.
  4. ii: the conditioned space has 7 equally likely outcomes, of which 3 satisfy the event. Thus P=3/7.
  5. iii: the conditioned space has 7 equally likely outcomes, of which 6 satisfy the event. Thus P=6/7.

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