NCERT Class 12 · Ch 13 Exercise 13.1 · Q5
NCERT Class 12 Maths · Chapter 13 Probability · Exercise 13.1 Question 5
P(A)=6/11, P(B)=5/11, P(A∪B)=7/11. Find (i) P(A∩B), (ii) P(A|B), (iii) P(B|A).
💡 Concept Hints
- Define the events and identify which event is being conditioned on.
- Use P(E|F)=P(E∩F)/P(F), or separate the possible sources before applying total probability and Bayes.
✅ Step-by-Step Solution
Final Answer: (i) 4/11; (ii) 4/5; (iii) 2/3.
- The intersection is P(A)+P(B)−P(A∪B)=6/11+5/11−7/11=4/11.
- Divide by P(B)=5/11 for P(A|B)=4/5; divide by P(A)=6/11 for P(B|A)=4/6=2/3.
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