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NCERT Class 12 · Ch 13 Exercise 13.1 · Q3

NCERT Class 12 Maths · Chapter 13 Probability · Exercise 13.1 Question 3

P(A)=0.8, P(B)=0.5, P(B|A)=0.4. Find (i) P(A∩B), (ii) P(A|B), (iii) P(A∪B).

💡 Concept Hints

  1. Define the events and identify which event is being conditioned on.
  2. Use P(E|F)=P(E∩F)/P(F), or separate the possible sources before applying total probability and Bayes.

✅ Step-by-Step Solution

Final Answer: (i) 8/25; (ii) 16/25; (iii) 49/50.
  1. (i) P(A∩B)=P(A)P(B|A)=0.8·0.4=0.32=8/25.
  2. (ii) P(A|B)=0.32/0.5=0.64=16/25.
  3. (iii) P(A∪B)=0.8+0.5−0.32=0.98=49/50.

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