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NCERT Class 12 · Ch 5 Exercise 5.5 · Q1

NCERT Class 12 Maths · Chapter 5 Continuity And Differentiability · Exercise 5.5 Question 1

Differentiate \(\cos{\left(x \right)} \cos{\left(2 x \right)} \cos{\left(3 x \right)}\) with respect to x; on R.

💡 Concept Hints

  1. Identify the domain and the inner and outer functions, or the relevant one-sided limits.
  2. Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.

✅ Step-by-Step Solution

Final Answer: \(- \frac{\sin{\left(2 x \right)} + 2 \sin{\left(4 x \right)} + 3 \sin{\left(6 x \right)}}{2}\)
  1. Work on R.
  2. Product rule: differentiate each variable factor once, keeping the other factors unchanged. Here \(\frac{d}{d x} \cos{\left(x \right)} \cos{\left(2 x \right)} \cos{\left(3 x \right)}\) = \(- \sin{\left(x \right)} \cos{\left(2 x \right)} \cos{\left(3 x \right)} - 2 \sin{\left(2 x \right)} \cos{\left(x \right)} \cos{\left(3 x \right)} - 3 \sin{\left(3 x \right)} \cos{\left(x \right)} \cos{\left(2 x \right)}\).
  3. Combining the terms gives y′ = \(- \frac{\sin{\left(2 x \right)} + 2 \sin{\left(4 x \right)} + 3 \sin{\left(6 x \right)}}{2}\).

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