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NCERT Class 12 · Ch 5 Exercise 5.5 · Q16

NCERT Class 12 Maths · Chapter 5 Continuity And Differentiability · Exercise 5.5 Question 16

Differentiate f(x)=(1+x)(1+x²)(1+x⁴)(1+x⁸) and find f′(1).

💡 Concept Hints

  1. Identify the domain and the inner and outer functions, or the relevant one-sided limits.
  2. Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.

✅ Step-by-Step Solution

Final Answer: \(15 x^{14} + 14 x^{13} + 13 x^{12} + 12 x^{11} + 11 x^{10} + 10 x^{9} + 9 x^{8} + 8 x^{7} + 7 x^{6} + 6 x^{5} + 5 x^{4} + 4 x^{3} + 3 x^{2} + 2 x + 1\); f′(1)=120.
  1. The geometric product equals 1+x+x²+⋯+x¹⁵ (equivalently (x¹⁶−1)/(x−1) for x≠1).
  2. Differentiate the polynomial: f′=1+2x+⋯+15x¹⁴.
  3. At x=1, the sum is 1+2+⋯+15=15·16/2=120.

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