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NCERT Class 12 · Ch 5 Exercise 5.5 · Q5

NCERT Class 12 Maths · Chapter 5 Continuity And Differentiability · Exercise 5.5 Question 5

Differentiate \(\left(x + 3\right)^{2} \left(x + 4\right)^{3} \left(x + 5\right)^{4}\) with respect to x; on R.

💡 Concept Hints

  1. Identify the domain and the inner and outer functions, or the relevant one-sided limits.
  2. Apply the appropriate differentiation or limit rule, keep all chain factors, and check exceptional points.

✅ Step-by-Step Solution

Final Answer: \(\left(x + 3\right) \left(x + 4\right)^{2} \left(x + 5\right)^{3} \left(9 x^{2} + 70 x + 133\right)\)
  1. Work on R.
  2. Product rule: differentiate each variable factor once, keeping the other factors unchanged. Here \(\frac{d}{d x} \left(x + 3\right)^{2} \left(x + 4\right)^{3} \left(x + 5\right)^{4}\) = \(4 \left(x + 3\right)^{2} \left(x + 4\right)^{3} \left(x + 5\right)^{3} + 3 \left(x + 3\right)^{2} \left(x + 4\right)^{2} \left(x + 5\right)^{4} + \left(x + 4\right)^{3} \left(x + 5\right)^{4} \left(2 x + 6\right)\).
  3. Combining the terms gives y′ = \(\left(x + 3\right) \left(x + 4\right)^{2} \left(x + 5\right)^{3} \left(9 x^{2} + 70 x + 133\right)\).

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